3x^2-13x+11=0

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Solution for 3x^2-13x+11=0 equation:



3x^2-13x+11=0
a = 3; b = -13; c = +11;
Δ = b2-4ac
Δ = -132-4·3·11
Δ = 37
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-\sqrt{37}}{2*3}=\frac{13-\sqrt{37}}{6} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+\sqrt{37}}{2*3}=\frac{13+\sqrt{37}}{6} $

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